
Yefim S. answered 11/26/21
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2cos2x - 7cosx + 3 = 0; (2cosx ;- 1)(cosx - 3) = 0; 2cosx - 1 = 0 or cos - 3 = 0'
cosx = 1/2; x = π/3 + 2πn, x = 5π/3 + 2πn, n∈Z
cosx - 3 = 0; cosx = 3, no solutions