J.R. S. answered 11/23/21
Ph.D. University Professor with 10+ years Tutoring Experience
Acetic acid (CH3COOH) is a weak acid.
Sodium hydroxide (NaOH) is a strong base.
The equivalence point is when moles of acid = moles of base
cm3 = ml and dm3 = L
CH3COOH + NaOH ==> CH3COONa + H2O ... balanced equation
a) mols NaOH used at equivalence = 15.24 ml NaOH x 1 L /1000 ml x 0.100 mol/L = 0.00152 mols NaOH
mols CH3COOH originally present = 0.00152 mols NaOH x 1 mol CH3COOH/mol NaOH = 0.00152 mols CH3COOH
concentration of CH3COOH = 0.00152 mols / 25.00 ml x 1000 ml / L = 0.0608 M = 0.0610 M (3 sig. figs.)
b) At equivalence, all of the CH3COOH has been converted to CH3COONa, which is the salt of a weak acid and a strong base. The pH of such a salt will have a basic pH because upon hydrolysis, you get the weak acid and the strong base. CH3COONa + H2O ==> CH3COOH + NaOH (basic solution)