
Yefim S. answered 11/23/21
Math Tutor with Experience
Direction vector PQ = <4 - 2,0 + 1, -1 - 3) = <2, 1, - 4).
Symmetric equation of line: (x - 4/2 = y/1 = (z + 1)/(- 4) = t;
So, x = 2t + 4; y = t, z = - 4t - 1
Kyle C.
asked 11/23/21Find parametric equations for the line that passes through the points P and Q. (Enter your answers as a comma-separated list. Let x, y, and z be in terms of t.)
P(2, −1, 3), Q(4, 0, −1)
Yefim S. answered 11/23/21
Math Tutor with Experience
Direction vector PQ = <4 - 2,0 + 1, -1 - 3) = <2, 1, - 4).
Symmetric equation of line: (x - 4/2 = y/1 = (z + 1)/(- 4) = t;
So, x = 2t + 4; y = t, z = - 4t - 1
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