J.R. S. answered 11/23/21
Ph.D. University Professor with 10+ years Tutoring Experience
3 Si(s) + 2 N2 (g) ➜ Si3N4 (s) ... balanced equation
A. What mass of nitrogen gas (molar mass: 28.014 g/mol) reacts with 10.00 g of silicon (molar mass: 28.085 g/mol)?
10.00 g Si x 1 mol Si / 28.085 g x 2 mol N2 / 3 mol Si x 28.014 g N2/mol = 6.650 g N2 (Ans. d)
B. How much Si3N4 (molar mass: 140.28 g/mol) is produced by reacting 10.00 g of silicon in excess nitrogen gas?
10.00 g Si x 1 mol Si / 28.085 g x 1 mol Si3N4 / 3 mol Si x 140.28 g Si3N4 / mol = 16.65 g Si3N4 (Ans. b)
C. If the actual amount of Si3N4 produced from 10.00 g of silicon is 11.31 g, what is the percent yield of the reaction?
% yield = actual yield / theoretical yield (x100%) = 11.31 g / 16.65 g (x100%) = 67.93% (Ans. d)