J.R. S. answered 11/23/21
Ph.D. University Professor with 10+ years Tutoring Experience
SiH4(g) + 2 O2(g) ➜ SiO2(s) + 2 H2O(l) ... ΔHrxn= –1,516.8 kJ
∆Hrxn = ∑n∆Hf products - ∑n∆Hf reactants
-1516.8 = [(-910.9) + (2x-285.8)] - [∆Hf SiH4 + 0]
-1516.8 = -1482.5 - ∆Hf SiH4
∆Hf SiH4 = +34.3 kJ/mol (Answer c)