Ammonia reacts with diatomic oxygen to form nitric oxide and water vapor:

Question

Ammonia reacts with diatomic oxygen to form nitric oxide and water vapor:

__ NH3 + __ O2 → __ NO + __ H2O

What is the theoretical yield of water, in grams, when 50.0 g O2 is allowed to react with excess ammonia?

I already balanced the equation:4NH3 + 5O2 → 4NO + 6H2O

Answer 1

4NH₃ + 5O₂ ==> 4NO + 6H₂O ... balanced equation

Using dimensional analysis and the stoichiometry of the balanced equation, we have the following:

50.0 g O₂ x 1 mol O₂ / 32 g x 6 mols H₂O / 5 mols O₂ x 18 g H₂O / mol = 33.8 g H₂O