Trigonometry Angles

Question

Find all solutions to the following triangle. (Round your answers for angles A, B, A', and B' to the nearest minute. Round your answers for sides a and a' to the nearest whole number. If either triangle is not possible, enter NONE in each corresponding answer blank.)

C = 23° 20', c = 342 m, b = 424 m

First triangle (assume B ≤ 90°):

A=  ?? degress    ?? feet

B= ?? degress     ?? feet

a= ?? m

 

Second triangle (assume B' > 90°):



A=  ?? degress    ?? feet

B= ?? degress     ?? feet

a= ?? m

Answer 1

As usual, Mark M. is correct.

In the first problem the altitude is 424*sin (70/3) which is approximately 168 m; therefore, a triangle is possible and the law of sines will get the necessary numbers.