J.R. S. answered 11/22/21
Ph.D. University Professor with 10+ years Tutoring Experience
In a previous answer to another of your questions, I provided the steps to draw the Lewis structure. I won't repeat that here.
NO2-
N has 5 ve + 6 ve for each O (12 ve) + 1 electron for the - sign = 18 ve
a) two resonance structures are O = N - O and O - N = O (both have a lone pair of electrons on the N and 2 lone pairs around the double bonded O and 3 lone pairs around the single bonded O)
b) For O = N - O formal charges are 0, 0, -1
For O - N = O formal charges are -1, 0, 0
c) The are no double bonds in the true structure as the O = N for each resonance structure is actually a bond and one half. In the experimental structure there is 1 double bond.