Consider the following reaction at 25 °C: 3 NiO(s) + 2 NH₃(g) → 3 Ni(s) + N₂(g) + 3 H₂O(g) If ∆G° = -18.1 kJ/mol, determine the value of the equilibrium constant at 25 °C.

Answer 1

3NiO(s) + 2NH₃(g) ==> 3Ni(s) + N₂(g) + 3H₂)(g)

∆Gº = -RT ln K

R = 8.314 J/molK = 0.008314 kJ/molK

T = 25 + 273 = 298K

-18.1 kJ/mol = -(0.008314 kJ/molK)(298K) ln K

ln K = 7.31

K = 1489