NEED ASAP!!! let θ =sin ^-1 √3 /7 which quadrant is the terminal side of θ in? Explain your reasoning.

Question

theta= sin^-1 √3 ÷7

Answer 1

The range of y = Sin^-1x is [-π/2, π/2] and the domain is [-1,1]. The inverse sine of a positive number in the interval (0, 1] lies in quadrant 1 while the inverse sine of a negative number in the interval [-1, 0) lies in quadrant 4.

So, Sin^-1(√3/7) lies in quadrant 1.