plz help with my stats hw

Question

If n=460 and ˆpp^ (p-hat) =0.64, find the margin of error at a 99% confidence level

Give your answer to three decimals

Answer 1

margin of error = critical z * standard error

critical z for 99% CI = 2.58

standard error = sqrt(phat * (1 -phat)/n) = sqrt(0.64 * 0.36/460)= 0.022

margin of error = 2.58 * 0.022 = 0.057