
Savannah J.
asked 11/19/21I need help with trig ASAP !
We know the following values.
sinA=4/5
cosB=√3/2
Give the exact value of Sin(A+B)
1 Expert Answer

Michael M. answered 11/19/21
Math, Chem, Physics, Tutoring with Michael ("800" SAT math)
I'm guessing you're using the sum identities
sin(A+B) = sin(A)cos(B) + sin(B)cos(A)
We're given sin(A) and cos(B)
Now we just need cos(A) and sin(B)
To get cos A, we can construct a triangle.
sin(A) = 4/5, so make a triangle with angle A and 4 being the opposite side and 5 being the hypotenuse.
We get a 3-4-5 triangle here and see that cos(A) = 3/5
We also could have used the property: sin2A + cos2A = 1 and solved.
(4/5)2 + cos2A = 1
cos2A = 1 - (4/5)2 = 9/25
cos A = √(9/25) = 3/5
Solve for sin(B) in a similar way and plug into the first equation
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UPENDRACHARY K.
Sin (A+B)=sinAcosB+cos Asin B =4/5*(√3/2)+3/5*1/2 =(3+4√3)/211/19/21