Geometry need help????

Question

Line p has an equation of y=–8x+6.Line q,which is perpendicular to line p,includes the point (2,–2).What is the equation of line q?

Answer 1

The key word here is perpendicular. The slope of a line perpendicular to another is the negative reciprocal, that is, -1/x. The slope of the line p is -8, so the slope of line q is the negative reciprocal, 1/8. Now that we know the slope and the point of line q, we can use the slope-intercept form, y = mx + b, or the point-slope form, y - y₁ = m(x - x₁), to find the equation of line q.

slope-intercept form

So substitute 1/8 in for m, 2 for x, and -2 for y into the slope-intercept form to solve for b. Once you find b, rewrite the equation with the slope (m) and intercept (b). There should be an x and a y in your final answer.

point-slope form

So substitute 1/8 in for m, 2 for x₁, and -2 for y₁ into the point-slope form. Then solve for y in order to get it to the slope-intercept form.

Answer 2

Lani, hope this helps, but please let me know