Calculate the energy emitted when a line with 2166 nm is formed . Given h=6.6256 x 10⁻³⁴ Js and c = 3.00 x 10⁸ ms⁻¹

Answer 1

Sarah,

Use the expression E = hc/λ

E = energy = ?

h = Planks constant = 6.6256x10^-34 Js

c = speed of light = 3.00x10⁸ ms^-1

λ = wavelength = 2166 nm, but we need to put this into m since that is the unit for c. λ = 2.166x10^-6 m

Solving for E we have...

E = (6.6256x10^-34 Js)(3.00x10⁸ ms^-1) / 2.166x10^-6 m

E = 9.18x10^-20 J