(secx+cscx)/(1+tanx)=
(1/cosx+1/sinx)/(1+sinx/cosx)=
[(sinx+cosx)/(sinx cosx)]/[(cosx+sinx)/cosx]=
[(sinx+cosx)/(sinx cosx)][(cosx)/(sinx+cosx)]=
cosx/(sinx cosx)=
1/sinx
John G.
asked 11/15/21(secx + cscx) / (1 + tanx)
(secx+cscx)/(1+tanx)=
(1/cosx+1/sinx)/(1+sinx/cosx)=
[(sinx+cosx)/(sinx cosx)]/[(cosx+sinx)/cosx]=
[(sinx+cosx)/(sinx cosx)][(cosx)/(sinx+cosx)]=
cosx/(sinx cosx)=
1/sinx
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