The pOH of a basic solution is 6.29. What is [H⁺]?

Answer 1

pOH + pH = 14

pH = 14 - pOH

pH = 14 - 6.29

pH = 7.71

pH = -log[H^+]

[H⁺] = 1x10^-pH

[H⁺] = 1x10^-7.71

[H⁺] = 1.95x10^-7 M

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pOH = -log[OH^-]

[OH^-] = 1x10^-6.29 = 5.13x10^-7 M

[OH^-][H⁺] = 1x10^-14

[H⁺] = 1x10^-14 / 5.13x10^-7

[H⁺] = 1.95x10^-7 M