
Dayv O. answered 11/09/21
Caring Super Enthusiastic Knowledgeable Trigonometry Tutor
pi<theta<3pi/2
implies pi/2<theta/2<3pi/4
for theta/2 therefore cos <0 and sin >0 (second quadrant)
for theta cos(theta)=-4/5 since tan(theta)=3/4 the hypotenuse is 5 and x coordinate -4
sin(theta/2)= +√(1-(-4/5)) the ambiguity in front of square root is resolved to + (second quadrant)
cos(theta/2)= -√(1+(-4/5)) the ambiguity in front of square root is resolved to - (second quadrant)
tan(theta/2)=[sin(theta/2)]/cos(theta/2)]