J.R. S. answered 11/09/21
Ph.D. University Professor with 10+ years Tutoring Experience
4.7kg x 1000 g/kg = 4700 g
q = (4700 g)(0.4494 J/gº)(-167º)
q = -352,734 J of heat transferred = -350,000 J ( 2 sig. figs.) = -350 kJ (2 sig. figs.)
Ariel C.
asked 11/09/21The specific heat of iron is 0.4494 J/g x oC. How much heat is transferred when a 4.7 kg piece of iron is cooled from 180 oC to 13 oC? Remember you must use the same units so you will have to convert your mass to grams before you beg
J.R. S. answered 11/09/21
Ph.D. University Professor with 10+ years Tutoring Experience
4.7kg x 1000 g/kg = 4700 g
q = (4700 g)(0.4494 J/gº)(-167º)
q = -352,734 J of heat transferred = -350,000 J ( 2 sig. figs.) = -350 kJ (2 sig. figs.)
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