Heat Transfer/Specific Heat Problems. Step-by-step

Question

How much heat is lost when a 64 g piece of copper cools from 375 oC, to 26 oC? (The specific heat of copper is 0.38452 J/g x oC). Place your answer in k

Answer 1

This is of the same ilk as your previous question (and you subsequent questions), so after this, you should be able to answer the others that you've posted.

q = mC∆T (this is the equation that can be used for all of your questions)

q = heat = ?

m = mass = 64 g

C = specific heat = 0.38452 J/gº

∆T = change in temperature = 26 - 375 = -349º

q = (64 g)(0.38452 J/gº)(-349º)

q = -8588 J (note the negative sign indicating heat is being LOST from the piece of copper as it cools)