Yefim S. answered • 11/08/21

Math Tutor with Experience

Let x is width and height. Then length is (62 - 2x)., then volume V(x) = x^{2}(62 - 2x) = 62x^{2} - 2x^{3};

V'(x) = 124x - 6x^{2} = 0; x = 0 or x = 62/3; V''(x) = 124 - 12x; V''(62/3) = 124 - 248 = - 124 < 0. So, we have maximum volume, max V = V(62/3) = (62/3)^{2}(62 - 124/3) = (62/3)^{3} = 427.11 in^{3}.

Nudar H.

Why did we take 64-2x??11/12/21