dilution chemistry

Question

A chemist must dilute 69.8mL of 142. mM aqueous barium chlorate Ba(ClO3)2 solution until the concentration falls to 53.0 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume.

Calculate this final volume, in liters. Round your answer to 3 significant digits.

Answer 1

V1M1 = V2M2

V1 = initial volume = 69.8 ml

M1 = initial molarity = 142. mM

V2 = final volume = ?

M2 = final molarity = 53.0 mM

Solve for V2 ...

V2 = V1M1 / M2

V2 = (69.8 ml)(142 mM) / 53.0 mM

V2 = 187 mls final volume