Chemistry in uni

Question

Hey!

0,100 L of 0,100 M NaCl (aq) is mixed with 0,500 L of 0,200 M NaF (aq). What is the concentration (molar) of Na⁺ in the mixture?

Thanks for helping me out :)

Answer 1

moles Na⁺ from NaCl

0.100 L x 0.100 mol/L = 0.01 mol Na⁺

moles Na⁺ from NaF

0.500 L x 0.200 mol/L = 0.1 mol Na⁺

Total mols Na+ = 0.01 mols + 0.10 mols = 0.110 mols Na+

Total volume = 0.100 L + 0.500 L = 0.600 L

Concentration of Na⁺ = 0.110 mols / 0.600 L = 0.183 mol/L = 0.183 M