when you have 3.33 moles of (NH4)2Cr2O7, how many grams of N2 will be produced?

Question

(NH₄)₂Cr₂O₇ --> N₂ + Cr₂O₃ + 4H₂O

Answer 1

 --> N₂ + Cr₂O₃ + 4H₂O ... balanced equation

From this balanced equation you can use the stoichiometry (mole ratios) to answer the question.

3.33 mols (NH₄)₂Cr₂O₇ x 1 mol N2 / mol (NH₄)₂Cr₂O₇ = 3.33 mols N₂

3.33 mols N₂ x 28 g N₂/mol = 93.2 g N₂ formed