Rewrite the equation as log3(2x + 5) − log4x − 3 = 0.
Through logarithmic identities & Calculus, one can transform log3(2x + 5) − log4x − 3 = 0
to ln (2x + 5)/ln 3 − ln x/ln 4 − 3 = 0 and take the first derivative of ln (2x + 5)/ln 3 − ln x/ln 4 − 3
as [2 ÷ (2x + 5) ÷ ln 3] − [1 ÷ x ÷ ln 4].
By Newton's Method Of Root Approximation, build the Formula
x − {ln (2x + 5)/ln 3 − ln x/ln 4 − 3} ÷ [2 ÷ (2x + 5) ÷ ln 3] − [1 ÷ x ÷ ln 4].
A graphing calculator shows y = ln (2x + 5)/ln 3 − ln x/ln 4 − 3 going to 0
around x = 0.13. The table below shows evaluation of the Formula with
x initially at 0.13. Each evaluation of the formula is given back to the
Formula as the new input value of x.
x--------------------------------------------x − {ln (2x + 5)/ln 3 − ln x/ln 4 − 3} ÷ [2 ÷ (2x + 5) ÷ ln 3] − [1 ÷ x ÷ ln 4]
0.13---------------------------------------------------0.1266987741
0.1266987741--------------------------------------0.1267428895
0.1267428895--------------------------------------0.1267428977
0.1267428977--------------------------------------0.1267428977
The last line of the table gives the last evaluation of the Formula as identical to the last x input;
x = 0.1267428977 is then the value of x sought.
This value of x = 0.1267428977 gives 2x + 5 as 5.253485795.
Then equate 3G to 5.253485795 which leads to Gln 3 = ln 5.253485795 or G = 1.509988405.
Also equate 4P to 0.1267428977 which leads to Pln 4 = ln 0.1267428977 or P = -1.490011595.
G − P or 1.509988405 − -1.490011595 does show log3(2x + 5) − log4x as equal to 3.