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Use the properties of logarithms to write the expression as a single logarithm:

7 ln x - 1/4 ln y
 
I would be very grateful for some help! Thanks for reading!
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2 Answers

logcan = n*logca

                                a

logca - logcb = logc --- 
                                b

logca + logcb = logc(ab) 
~~~~~~~~~~~~~~~~~~~ 

7 ln x  - (1/4) ln y =

ln x7  -  ln y1/4 =

       x7             x7  
ln ------ = ln ----
     y1/4           4√y
7 ln(x)-(1/4)ln(y)
7 ln(x)=ln(x^7)
(1/4)ln(y)=ln[y^(1/4)]
ln(x^7)-ln[y^(1/4)]=ln[(x^7)/(y^(1/4))]