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Log (3x+5) = 1 + (log (x-1)

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3 Answers

woops, my bad x = 15/7

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I think there is an error here.  Since the bases are the same when you move the log(x-1) to the left, we could use the quotient rule of logs to get Log(3x+5)/(x-1)=1...which we can rewrite in exponential form; 10^1=(3x+5)/(x-1)...which gives us 10x-10=3x+5....7x=15....x=15/7 

Hi Thomas. There is no any evidence, that given logarithm is natural (ln).

Since the bases are the same when you move the log(x-1) to the left, we could use the quotient rule of logs to get Log(3x+5)/(x-1)=1...which we can rewrite in exponential form; 10^1=(3x+5)/(x-1)...which gives us 10x-10=3x+5....7x=15....x=15/7