How many grams of Copper (II) phthalocyanine would be produced by the complete cyclotetramerization of 4.910 moles of phthalonitrile in the presence of excess copper (II) chloride?

Answer 1

First we need the correctly balanced equation for the reaction taking place:

4 C₈H₄N₂ + Cu²⁺ ==> C₃₂H₁₆CuN₈ ... balanced equation

4.910 mols C₈H₄N₂ x 1 mol C₃₂H₁₆CuN₈ / 4 mol C₈H₄N₂ = 1.228 mols Cu(II) phthalocyanine