
Doug C. answered 11/05/21
Math Tutor with Reputation to make difficult concepts understandable
There is a formula for the area of an equilateral triangle given its side length:
A = s2√3/4 , where s is the length of a side.
That formula is derived by dropping an altitude from a vertex. That altitude creates two congruent triangles (HL) so the base is divided into two equal segments (s/2). Those two triangles are 30-60-90 triangles, so the altitude has a length that is √3 times the short leg (s/2). So altitude = s√3/2.
The area is 1/2 bh. The base is s (one of the sides), the altitude is s√3/2, so A = 1/2 (s) (s√3/2).
Just substitute 6 for s into the area formula and simplify to find A.