3. A metal with a specific heat of 0.78 J/g o C requires 45 J of heat to raise the temperature by 2 o C. What is the mass of the metal?

Answer 1

q = mC∆T

q = heat = 45 J

m = mass = ?

C = specific heat = 0.78 J/gº

∆T = change in temperature = 2º

Solving or m, we have...

m = q / C∆T = 45 J / (0.78 J/gº)(2º)

m = 28.8 g = 29 g (2 sig. figs.)