AP CHEMISTRY GAS LAWS SUMMARY

Question

In an industrial process, 200. L of a gas at 91.kPa and 21 degrees C is compressed into a vessel that has a volume of 15.2 L and heated to 420. degrees C. What is its final pressure?

Answer 1

Given:

V1 = initial volume = 200. L

P1 = initial pressure = 91. kPa

T1 = initial temp = 21C +273 = 294K

V2 = final volume = 15.2 L

T2 = final temp = 420C + 273 = 693K

Use the combined gas law: P1V1/T1 = P2V2/T2 and solve for P2...

P2 = P1V1T2 / V2T1 = (91)(200)(693) / (15.2)(294)

P2 = 2822 kPa = 2800 kPa (2 sig figs)