Writing Equations of parallel and perpendicular lines

Question

Write the equation of a line that is parallel to y=0.6x+3 and that passes through the point (-3,-5)

Answer 1

Parallel lines have the same slope. Therefore, m=0.6

Now, we can pick plug it into the point slope equation along with the point given to find the equation of the line.

(y-y1) = m(x-x1)

(y-(-5)) = 0.6(x-(-3)) Simplify the subtraction

y+5 = 0.6(x+3) Distribute 0.6

y+5 = 0.6x+1.8 Subtract 5 from both sides of the equation

y=0.6x-3.2