When an electron in a hydrogen atom falls from n = 5 → n = 2, the amount of energy the electrons carries is - 4.20 x 10-19 J.

Question

What is the energy of the photon of light? What is the energy in Joule/mol of photons?

Answer 1

The energy calculated for the fall from n = 5 to n = 2 is for 1 electron.

Thus, the energy of the photon of light is 4.20x10^-19 J

The energy in Joule / mole of photons would be...

4.20x10^-19 J / photon x 6.02x10²³ photons / mol = 2.53x10⁵ J / mol photons