J.R. S. answered 10/30/21
Ph.D. University Professor with 10+ years Tutoring Experience
So, what is the phase of ethanol at -59.7ºC. Looking it up, I find it to be a liquid at this temperature because the freezing point is -114ºC.
Since it is a liquid at this temperature, and we want to boil it, we also need to know the specific heat of liquid ethanol, as well as the ∆Hvaporization and the boiling point, Again, looking up these values I find them to be:
specific heat (C) = 2.40 J/gº
∆Hvap = 838.3 J/g
BP = 78.2ºC
Now using all of these constants, we can approach the answer to the question.
(1) heat needed to raise 37.6 g ethanol from -59.7º to the boiling point of 78.2ºC:
q = mC∆T
q = (37.6 g)(2.40 J/gº)(137.9º) = 12,444 J
(2) heat needed to boil 37.6 g at 78.2º (phase change):
q = m∆Hvap = (37.6 g)(838.3 J/g) = 31,520 J
Total heat needed = 12,444 J + 31,520 J = 43,964 J = 43.9 kJ