When the following redox reaction, MnO4- + Zn = Mn2+ + Zn2+ is balanced, the number of electron/s transferred is ______

Answer 1

MnO₄^- + Zn ==> Mn²⁺ Zn²⁺

Mn in MnO₄^- has oxidation number of 7+

Mn in Mn²⁺ has oxidation number of 2+

Mn has gained 5 electrons (reduction)

Zn in Zn has oxidation number of zero

Zn in Zn²⁺ has oxidation number of 2+

Zn has lost 2 electrons (oxidation)

In order for the number of electrons gained be equal to the number of electrons lost, we must multiply the reduction reaction by 2 and the oxidation reaction by 5.

Thus the number of electrons transferred is TEN