J.R. S. answered 10/29/21
Ph.D. University Professor with 10+ years Tutoring Experience
2Na(s) + 2H2O(l) ==> 2NaOH(aq) + H2(g) ... balanced equation
10.0 g Na x 1 mol Na / 23.0 g x 1 mol H2 / 2 mol Na x 2 g H2/ mol = 0.435 g H2 gas
Sarah Kathryn S.
asked 10/29/21Alkali metals react violently with water. How much Hydrogen gas (in g) is produced when 10.0 g of sodium reacts with excess water according to the following equation?
2Na + 2H2O ----> 2NaOH + H2
J.R. S. answered 10/29/21
Ph.D. University Professor with 10+ years Tutoring Experience
2Na(s) + 2H2O(l) ==> 2NaOH(aq) + H2(g) ... balanced equation
10.0 g Na x 1 mol Na / 23.0 g x 1 mol H2 / 2 mol Na x 2 g H2/ mol = 0.435 g H2 gas
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