Help I dont understand Stiochiometry

Question

Using the following equation how many grams of pure oxygen do you need to consume 879 g of glucose:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy

Answer 1

Alison,

Stoichiometry is nothing more that the mole ratios in the balanced equation.

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy

The stoichiometry of this balanced equation tells us that 1 mol C₆H₁₂O₆ reacts with 6 mols O₂ to produce 6 mols CO₂ and 6 mols H₂O

Now, we use this information along with molar mass of C₆H₁₂O₆ (180 g/mol) and the molar mass of O₂ (32 g/mol) to answer the question:

879 g C₆H₁₂O₆ x 1 mol C₆H₁₂O₆ / 180 g x 6 mol O2 / 1 mol C₆H₁₂O₆ x 32 g O2/mol O2 = 938 g O₂ used