Calculate the standard enthalpy change

Question

Calculate the standard enthalpy change for the reaction at 25 degrees C.

2CH3OH(g)+3O2(g)⟶2CO2(g)+4H2O(g)

Δ𝐻∘rxn= ?KJ

Answer 1

2CH₃OH(g) + 3O₂(g)⟶2CO2 (g) + 4H₂O(g)

-201................0................-393.5.......-241.8

∆H_rxn = ∑n∆H_products - ∑n∆H_reactants

∆H_rxn = [(2 * -393.5 + 4 * -241.8)] - [2 * -201]

∆H_rxn = -787 + -(967.2) - (-402)

∆H_rxn = -1352.2 kJ