Curt A. answered 04/15/13
ALL Math, from Pre-Algebra to Partial Differential Equations
So √27 / √75 =
the top first √27 = √9 * √3 = 3 * √3
now the bottom part √75 = √25 * √3 = 5 * √3
and so the √3 cancells out leaving = 3/5
Randy D.
asked 03/20/13Simplify
Be sure to write your answer in lowest terms.
Curt A. answered 04/15/13
ALL Math, from Pre-Algebra to Partial Differential Equations
So √27 / √75 =
the top first √27 = √9 * √3 = 3 * √3
now the bottom part √75 = √25 * √3 = 5 * √3
and so the √3 cancells out leaving = 3/5
Nataliya D. answered 03/20/13
Patient and effective tutor for your most difficult subject.
√(ab) = √a · √b
√(a/b) = (√a) / (√b)
~~~~~~~~
√(27/75) = (√27)/(√75) = (√(3 · 9)) / (√(3 · 25)) = 3√3 / 5√3 = 3/5
3 √3
5 √3
3
5
Robert J. answered 03/20/13
Certified High School AP Calculus and Physics Teacher
sqrt(27/75)
= sqrt(9/25), after cancelling 3.
= 3/5 <==Answer, since (3/5)^2 = 9/25
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