Octatomic sulfur (S8) reacts with bromine (Br2) to produce sulfur hexabromide (SBr6). If 8.25 moles Br2, and plenty of S8 were used, what would be the theoretical yield (in moles) of SBr6?

Answer 1

First, we should write the correctly balanced equation for the reaction taking place:

S₈ + 24 Br₂ ==> 8 SBr₆ ... balanced equation

Now, we can simply use dimensional analysis to find the moles of SBr6 theoretically produced in the presence of excess S8:

8.25 mols Br₂ x 8 mols SBr₆ / 24 mols Br₂ = 2.75 mols SBr₆