J.R. S. answered 10/21/21
Ph.D. University Professor with 10+ years Tutoring Experience
2KClO3(s) ==> 2KCl(s) + 3O2(g) ... balanced equation for decomposition of KClO3(s)
molar mass KClO3 = 122.5 g/mol
46.1 g KClO3 x 1 mol / 122.5 g x 3 mols O2 / 2 mols KClO3 = 0.564 moles of O2 produced
Combustion of methane (CH4):
CH4 + 2O2 ==> CO2 + 2H2O ... balanced equation
molar mass CH4 = 16 g/mol
8.50x10-3 g CH4 x 1 mol / 16 g x 1 mol CO2 / mol CH4 x 44 g CO2/ mol = 0.0234 g CO2