J.R. S. answered 10/21/21
Ph.D. University Professor with 10+ years Tutoring Experience
molar mass (NH4)2SO4 = 132 g / mol
Since we are interested only in the nitrogen (N), we want to find how much N is present in each mol of (NH4)2SO4. One mol (NH4)2SO4 contains 2 mols N. The mass of N per mol of (NH4)2SO4 is ...
1 mol (NH4)2SO4 x 2 mol N / mol (NH4)2SO4 x 14 g N / mol N = 28 g N
% N = 28 g / 132 g (x100%) = 21.2% N
1 lb N x 454 g N / lb = 454 g N required
0.212 x = 454 g
x = 2142 g (NH4)2SO4 required per year
Jonah Mae Y.
thank you sir, it help me to understand this problem now.10/22/21