J.R. S. answered 10/15/21
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Use the equation: q = mC∆T
q = heat = ?
m = mass = 50 g
C = specific heat = 4.184 J/gº
∆T = change in temperature =150º - 20º = 130º
q = (50 g)(4.184 J/gº)(130º) = 27,196 J