The glycol-water mixture used as coolant has a glycol content of22 % and a total mass of 20 kg. If the mixture is to be concentrated to 40 %, how much pure glycol must be added to the mixture?
Please solve this math anyone.
Use 1 equation for total mass/volume and another equation for total concentration as shown below:
20 kg + X kg = (20 + X) kg
20 kg at 22% added to X kg at 100% = a total of (20 + X)kg at 40% concentration
20kg*(0.22) + Xkg*(1.00) = (20 + X)(0.40) Solve for X
4.4 + x = 8 + 0.4x
0.6x = 3.6
x = 6
Add 6 kg of 100% glycol to the mixture to make 26 kg of 40%.