The specific heat of a certain type of cooking oil is 1.75 J/(g·°C). How much heat energy is needed to raise the temperature of 2.82 kg of this oil from 23 °C to 191 °C

Answer 1

Ali,

Use the equation q = mC∆T

q = heat = ?

m = mass = 2.82 kg x 1000 g/kg = 2820 g

C = specific heat = 1.75 J/gº

∆T = change in temperature =191 - 23 = 168º

q = (2820 g)(1.75 J/gº)(168º)

q = 829,080 J = 829 kJ (3 sig. figs.)