I’m not too sure how to solve this

Question

Question 23:

calculate the root mean square velocity (m/s) of the CH₄ molecules in a sample of CH₄ gas at 546K.

Answer 1

rms = √3RT/M

R = 8.314 J/Kmol

T = temp in K = 546K

M = molar mass of CH4 in kg/mol = 16 g/mol x 1kg/1000 g = 0.016 kg/mol

rms = √(3)(8.314 J/Kmol)(546K) / 0.016 kg/mol

To get proper units for rms (velocity), we will change Joules to kg-m²/s² since 1 J = 1 kg-m²/s²

rms = √(3)(8.314 1 kg-m²/s²)(546K) / 0.016 kg/mol

rms = 923 m/s