Percent of error

Question

After completing the experiment a student extracts a sample of calcium carbonate with a mass of 0.819 grams from an antacid tablet that claims to have 1000 mg of calcium carbonate what is the percent error in this students experiment? Round your answer to two decimal places

Answer 1

% error is (accepted value - measured value / accepted value) (x100%)

0.819 g x1000 mg / g = 819 mg

% error = 1000 - 819 / 1000 (x100%) = 18.10% error