Write a equation for, perpendicularl to 2y =x+16 passes through (0,-5)

Question

Write a equation for, perpendicularl to 2y =x+16 passes through (0,-5)

Answer 1

2y = x + 16

express as y = mx + b

where m is slope and b is y-intercept

y = 1/2x + 8. slope m = 1/2. slope of perpendicular line is negative reciprocal= - 2

Since the line passes through (0,-5), the y-intercept is -5

so equation of line is:

y = -2x - 5