If 6.39 g of CuNO3 is dissolved in water to make a 0.180 M solution, what is the volume of the solution in milliliters?

Answer 1

molar mass CuNO3 = 125.6 g/mol

0.180 M = 0.180 mol/L

6.39 g x 1 mol / 126.5 g = 0.0505 mols

So, how many liters do you have to have so the concentration is 0.180 mol/L?

00505 mols / x L = 0.180 mol / 1 L

x = 0.281 L or 281 mls