A man walks 7 km due north, 6 km due east, and then 4 km due north. How far is he from his starting point?

Answer 1

Use the Pythagorean Theorem:

c² = (7+4)²+(6)²

c² = 121+36

c² = 157

c = (157)^1/2 ≈ 12.53 km