Chem help please

Question

Combining 0.341 mol Fe2O3 with excess carbon produced 17.3 g Fe. Fe2O3+3C⟶2Fe+3CO What is the actual yield of iron in moles?

actual yield:

What is the theoretical yield of iron in moles?

theoretical yield:

What is the percent yield?

percent yield:

Answer 1

Actual yield of Fe in moles:

17.3 g Fe x 1 mol Fe / 55.85 g = 0.310 mol (3 sig. figs.)

Theoretical yield of Fe in moles:

0.341 mol Fe2O3 x 2 mol Fe / 1 mol Fe2O3 = 0.682 mols Fe

Percent yield:

0.310 mol / 0.682 mol (x100%) = 45.5% yield